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8x^2-4=508
We move all terms to the left:
8x^2-4-(508)=0
We add all the numbers together, and all the variables
8x^2-512=0
a = 8; b = 0; c = -512;
Δ = b2-4ac
Δ = 02-4·8·(-512)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16384}=128$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-128}{2*8}=\frac{-128}{16} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+128}{2*8}=\frac{128}{16} =8 $
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